SYNTENE LEARN . SAT MATH . ALGEBRA
For what value of k do the equations 6x - 3y = 12 and kx - 6y = 18 have no solution?
Answer: D) 12. Multiply the first equation by 2: 12x - 6y = 24. For no solution with kx - 6y = 18, k = 12 but 24 \neq 18, so the lines are parallel.
Step-by-step solution
Multiply the first equation by 2: 12x - 6y = 24. For no solution with kx - 6y = 18, k = 12 but 24 \neq 18, so the lines are parallel.
Common mistake
Picking a k that makes the equations identical (infinitely many solutions) instead of parallel.
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What is the answer to For what value of k do the equations 6x - 3y = 12 and kx - 6y = 18 have no solution?
Answer: D) 12. Multiply the first equation by 2: 12x - 6y = 24. For no solution with kx - 6y = 18, k = 12 but 24 \neq 18, so the lines are parallel.
How do you solve it?
Multiply the first equation by 2: 12x - 6y = 24. For no solution with kx - 6y = 18, k = 12 but 24 \neq 18, so the lines are parallel.
What mistake do most students make?
Picking a k that makes the equations identical (infinitely many solutions) instead of parallel.
What SAT topic is this?
Algebra. Practice more free Algebra questions with instant feedback at Syntene Learn.